Integrand size = 21, antiderivative size = 89 \[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=-\frac {d \left (d^2-e^2 x^2\right )^{1+p}}{2 e^2 (1+p)}+\frac {1}{3} e x^3 \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},-p,\frac {5}{2},\frac {e^2 x^2}{d^2}\right ) \]
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Time = 0.02 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.00, number of steps used = 4, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.190, Rules used = {778, 267, 372, 371} \[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=\frac {1}{3} e x^3 \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},-p,\frac {5}{2},\frac {e^2 x^2}{d^2}\right )-\frac {d \left (d^2-e^2 x^2\right )^{p+1}}{2 e^2 (p+1)} \]
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Rule 267
Rule 371
Rule 372
Rule 778
Rubi steps \begin{align*} \text {integral}& = d \int x \left (d^2-e^2 x^2\right )^p \, dx+e \int x^2 \left (d^2-e^2 x^2\right )^p \, dx \\ & = -\frac {d \left (d^2-e^2 x^2\right )^{1+p}}{2 e^2 (1+p)}+\left (e \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p}\right ) \int x^2 \left (1-\frac {e^2 x^2}{d^2}\right )^p \, dx \\ & = -\frac {d \left (d^2-e^2 x^2\right )^{1+p}}{2 e^2 (1+p)}+\frac {1}{3} e x^3 \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \, _2F_1\left (\frac {3}{2},-p;\frac {5}{2};\frac {e^2 x^2}{d^2}\right ) \\ \end{align*}
Time = 0.14 (sec) , antiderivative size = 89, normalized size of antiderivative = 1.00 \[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=-\frac {d \left (d^2-e^2 x^2\right )^{1+p}}{2 e^2 (1+p)}+\frac {1}{3} e x^3 \left (d^2-e^2 x^2\right )^p \left (1-\frac {e^2 x^2}{d^2}\right )^{-p} \operatorname {Hypergeometric2F1}\left (\frac {3}{2},-p,\frac {5}{2},\frac {e^2 x^2}{d^2}\right ) \]
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\[\int x \left (e x +d \right ) \left (-e^{2} x^{2}+d^{2}\right )^{p}d x\]
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\[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=\int { {\left (e x + d\right )} {\left (-e^{2} x^{2} + d^{2}\right )}^{p} x \,d x } \]
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Time = 1.19 (sec) , antiderivative size = 85, normalized size of antiderivative = 0.96 \[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=d \left (\begin {cases} \frac {x^{2} \left (d^{2}\right )^{p}}{2} & \text {for}\: e^{2} = 0 \\- \frac {\begin {cases} \frac {\left (d^{2} - e^{2} x^{2}\right )^{p + 1}}{p + 1} & \text {for}\: p \neq -1 \\\log {\left (d^{2} - e^{2} x^{2} \right )} & \text {otherwise} \end {cases}}{2 e^{2}} & \text {otherwise} \end {cases}\right ) + \frac {d^{2 p} e x^{3} {{}_{2}F_{1}\left (\begin {matrix} \frac {3}{2}, - p \\ \frac {5}{2} \end {matrix}\middle | {\frac {e^{2} x^{2} e^{2 i \pi }}{d^{2}}} \right )}}{3} \]
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\[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=\int { {\left (e x + d\right )} {\left (-e^{2} x^{2} + d^{2}\right )}^{p} x \,d x } \]
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\[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=\int { {\left (e x + d\right )} {\left (-e^{2} x^{2} + d^{2}\right )}^{p} x \,d x } \]
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Timed out. \[ \int x (d+e x) \left (d^2-e^2 x^2\right )^p \, dx=\int x\,{\left (d^2-e^2\,x^2\right )}^p\,\left (d+e\,x\right ) \,d x \]
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